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# Balanced Equation Circus Trains: An Alexander Calder Connection

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A unique, differentiated common core problem-solving activity! Integrate math and art to create a circus train, inspired by Alexander Calder’s traveling circus or any circus book or theme. Many varying levels of difficulty included to meet everyone’s needs! Detailed lesson plan will help you implement this experience, sure to enhance children’s understanding of balanced equations, addition, and number relationships. A SMARTBoard lesson is included, but everything is also included as a hard copy so you do not need a SMARTBoard to implement this activity. Makes an impressive classroom display when completed!

This activity is part of an Alexander Calder Artist Study, which is a portion of our complete Artist Biography Unit.

Go to this link to read a parent's testimony to the power and effectiveness of our
Artist Biography Unit:
http://goodmenproject.com/families/teaching-art-form-gmp/

Go go our store to find individual artist activities and complete
Artist Studies about the following artists: Michelangelo,
Edgar Degas, Claude Monet, Pablo Picasso, Georgia O’Keeffe, Alexander Calder,
Jackson Pollock, Andy Warhol, and Andy Goldsworthy.
http://www.teacherspayteachers.com/Store/Ideas-For-Teaching

This learning experience is directly correlated with the Common Core State Standards:
Understand and apply properties of operations and the relationship between addition and subtraction.
CCSS.Math.Content.1.OA.B.3 Apply properties of operations as strategies to add and subtract.2 Examples: If 8 + 3 = 11 is known, then 3 + 8 = 11 is also known. (Commutative property of addition.) To add 2 + 6 + 4, the second two numbers can be added to make a ten, so 2 + 6 + 4 = 2 + 10 = 12. (Associative property of addition.)

CCSS.Math.Content.1.OA.C.6 Add and subtract within 20, demonstrating fluency for addition and subtraction within 10. Use strategies such as counting on; making ten (e.g., 8 + 6 = 8 + 2 + 4 = 10 + 4 = 14); decomposing a number leading to a ten (e.g., 13 – 4 = 13 – 3 – 1 = 10 – 1 = 9); using the relationship between addition and subtraction (e.g., knowing that 8 + 4 = 12, one knows 12 – 8 = 4); and creating equivalent but easier or known sums (e.g., adding 6 + 7 by creating the known equivalent 6 + 6 + 1 = 12 + 1 = 13).
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