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# QR Codes Addition and Subtraction Scavenger Hunt

K - 2nd
Standards
Resource Type
Formats Included
• PDF
Pages
10 pages

### Description

My first graders love using QR Codes as a math center; especially since QR Codes are involved! QR Codes instantly make activities more exciting and engaging for all learners. In this special QR Codes scavenger hunt activity, students will solve the equation to find sum/difference then search for that number on the QR Code task cards. Once they find the sum/difference on a card they will scan the QR Code below and be on to their next problem!

To access the QR Codes on each card you will need to download a free QR reader on your iPad, iPhone, iPod touch, or laptop (any of these devices, as long as it has a camera, will work!)

This QR Codes activity is a scavenger hunt and works a little differently than the typical task cards! Students will begin by scanning the QR Codes below the word "start." This card will read "Find the sum of 3+7." Students will then find the card with the number "10" on it and write it by number 2 (because that is the second card.) After writing their equation, students will then scan the QR Code below the number 10. This scan will read, "6-1=___." Students will search the room for the card with the sum "5." They will then write this full equation by the number 3. Students will continue in this manner to find the rest of the equations!

This QR Codes math center activity aligns with the common core: 1.OA.C.6

Be sure to check out my other QR Code Common Core Centers and Activities
Total Pages
10 pages
N/A
Teaching Duration
30 minutes
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### Standards

to see state-specific standards (only available in the US).
Add and subtract within 20, demonstrating fluency for addition and subtraction within 10. Use strategies such as counting on; making ten (e.g., 8 + 6 = 8 + 2 + 4 = 10 + 4 = 14); decomposing a number leading to a ten (e.g., 13 - 4 = 13 - 3 - 1 = 10 - 1 = 9); using the relationship between addition and subtraction (e.g., knowing that 8 + 4 = 12, one knows 12 - 8 = 4); and creating equivalent but easier or known sums (e.g., adding 6 + 7 by creating the known equivalent 6 + 6 + 1 = 12 + 1 = 13).