# Solving System of Equations by Elimination - Multiply One Equation Maze    Subject
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The Solving System of Equations by Elimination - Multiply One Equation Maze Assignment includes 24 problems. Students will determine the correct path to get from the start to the end of the maze by solving elimination problems. All systems can be solved by multiplying one equation- a variable needs an inverse for elimination. An answer key is also included.

This is a great activity for independent practice. You can assess students' comprehension of solving systems by elimination. Or have students work with a partner to complete the maze.

Solve systems of two linear equations in two variables algebraically, and estimate solutions by graphing the equations. Solve simple cases by inspection. For example, 3𝘹 + 2𝘺 = 5 and 3𝘹 + 2𝘺 = 6 have no solution because 3𝘹 + 2𝘺 cannot simultaneously be 5 and 6.
Understand that solutions to a system of two linear equations in two variables correspond to points of intersection of their graphs, because points of intersection satisfy both equations simultaneously.
Analyze and solve pairs of simultaneous linear equations.
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