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Valentine's Day Color By Number Subtraction

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Fern Smith's Classroom Ideas
17,716 Followers
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Grade Levels
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PDF (1 MB|12 pages)
TpT Digital Activity
Standards
CCSS2.OA.B.2
CCSS1.OA.C.6
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Fern Smith's Classroom Ideas
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DescriptionStandards2Reviews1Q&AFern Smith's Classroom IdeasMore fromFern Smith's Classroom Ideas

Description

St. Valentine's Day Color By Number Love Monsters Themed Subtraction - Your students will adore these Valentines Day Color Your Answer worksheets while learning and reviewing important skills at the same time! You will love the no prep, print and go ease of these printables. As always, answer keys are included. Valentines Day - Valentine's Day Math: Valentine's Day Fun! Valentine's Day Love Monsters Subtraction Facts - Color Your Answers Printables for St. Valentine's Day Subtraction in your classroom.

This Valentine's Day Love Monsters Subtraction Resource includes:

FIVE No Prep Printables that can be used for your math center, small group, RTI pull out, seat work, substitute days or homework, answer keys included too!

These high interest black and white printables are great for seat work, homework or small group work.

This resources is available in these larger bundles:

Valentines Day Love Monsters for Addition, Subtraction, Multiplication and Division and

Valentines Day Love Monsters for Addition and Subtraction

OR

Click here to buy this resource in the larger Valentine's Day Subtraction ONLY Bundle!

Terrific for an Emergency Sub Tub or Homework!

Click here for ALL my Color Your Answer Resources!

© Fern Smith's Classroom Ideas

Total Pages
12 pages
Answer Key
Included
Teaching Duration
1 Week
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Standards

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CCSS2.OA.B.2
Fluently add and subtract within 20 using mental strategies. By end of Grade 2, know from memory all sums of two one-digit numbers.
CCSS1.OA.C.6
Add and subtract within 20, demonstrating fluency for addition and subtraction within 10. Use strategies such as counting on; making ten (e.g., 8 + 6 = 8 + 2 + 4 = 10 + 4 = 14); decomposing a number leading to a ten (e.g., 13 - 4 = 13 - 3 - 1 = 10 - 1 = 9); using the relationship between addition and subtraction (e.g., knowing that 8 + 4 = 12, one knows 12 - 8 = 4); and creating equivalent but easier or known sums (e.g., adding 6 + 7 by creating the known equivalent 6 + 6 + 1 = 12 + 1 = 13).

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