Christmas Color by Number – Subtraction Within 20 | 8 Math Worksheets + Answer

Description

Bring Christmas cheer into your classroom with these fun and engaging Color-by-Number worksheets!

This set includes 8 Christmas-themed Subtraction pages (within 20) and 8 matching answer keys, perfect for morning work, math centers, early finishers, homework, or sub plans.

Each page features a cute Christmas picture—Santa, snowman, reindeer, gift, candy, wreath, Christmas tree, and snowball friends.
Students solve the Subtraction problems and color the picture using the code.

No-prep and ready to print!

These worksheets help students:

Build Subtraction fluency within 20
Strengthen number recognition
Improve focus and fine motor skills
Enjoy math with festive Christmas fun!

Perfect for Kindergarten & 1st Grade.

🎄 Make December math fun, stress-free, and colorful!

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Christmas Color by Number – Subtraction Within 20 | 8 Math Worksheets + Answer

Name: Christmas Color by Number – Subtraction Within 20 | 8 Math Worksheets + Answer
Brand: Happyminds Brightfutures
SKU: 15051877
Price: 3.50 USD
Availability: InStock

Happyminds Brightfutures

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$3.50

Highlights

Digital downloads

PDF

Grades

PreK - 1st

Subjects

Numbers, Other (Math)

Standards

CCSS1.OA.C.6

Description

These worksheets help students:

Build Subtraction fluency within 20
Strengthen number recognition
Improve focus and fine motor skills
Enjoy math with festive Christmas fun!

Perfect for Kindergarten & 1st Grade.

🎄 Make December math fun, stress-free, and colorful!

Report this resource to TPT

Reported resources will be reviewed by our team. Report this resource to let us know if this resource violates TPT's content guidelines.

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Questions & Answers

Standards

to see state-specific standards (only available in the US).

CCSS1.OA.C.6

Add and subtract within 20, demonstrating fluency for addition and subtraction within 10. Use strategies such as counting on; making ten (e.g., 8 + 6 = 8 + 2 + 4 = 10 + 4 = 14); decomposing a number leading to a ten (e.g., 13 - 4 = 13 - 3 - 1 = 10 - 1 = 9); using the relationship between addition and subtraction (e.g., knowing that 8 + 4 = 12, one knows 12 - 8 = 4); and creating equivalent but easier or known sums (e.g., adding 6 + 7 by creating the known equivalent 6 + 6 + 1 = 12 + 1 = 13).