Description
This bundle has stacks for your whole fraction unit! Print 5-10 copies of each Question Stack on different color card stock. Store in caddy for easy access for you and your students. Great for reviewing before assessments throughout the unit or extra practice at the end of the class period.
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Highlights
Grades
4th - 6th
Standards
CCSS5.NF.A.1
CCSS5.NF.B.4a
CCSS5.NF.B.5b
Tags
Pages
12
Description
This bundle has stacks for your whole fraction unit! Print 5-10 copies of each Question Stack on different color card stock. Store in caddy for easy access for you and your students. Great for reviewing before assessments throughout the unit or extra practice at the end of the class period.
Report this resource to TPT
Reported resources will be reviewed by our team. Report this resource to let us know if this resource violates TPT's content guidelines.
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Questions & Answers
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Standards
to see state-specific standards (only available in the US).
CCSS5.NF.A.1
Add and subtract fractions with unlike denominators (including mixed numbers) by replacing given fractions with equivalent fractions in such a way as to produce an equivalent sum or difference of fractions with like denominators. For example, 2/3 + 5/4 = 8/12 + 15/12 = 23/12. (In general, π’/π£ + π€/π₯ = (π’π₯ + π£π€)/π£π₯.)
CCSS5.NF.B.4a
Interpret the product (π’/π£) Γ π² as a parts of a partition of π² into π£ equal parts; equivalently, as the result of a sequence of operations π’ Γ π² Γ· π£. For example, use a visual fraction model to show (2/3) Γ 4 = 8/3, and create a story context for this equation. Do the same with (2/3) Γ (4/5) = 8/15. (In general, (π’/π£) Γ (π€/π₯) = π’π€/π£π₯.)
CCSS5.NF.B.5b
Explaining why multiplying a given number by a fraction greater than 1 results in a product greater than the given number (recognizing multiplication by whole numbers greater than 1 as a familiar case); explaining why multiplying a given number by a fraction less than 1 results in a product smaller than the given number; and relating the principle of fraction equivalence π’/π£ = (π―Γπ’)/(π―Γπ£) to the effect of multiplying π’/π£ by 1.
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